Kaplansky Idempotent Conjecture
Canonical statement
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If \(G\) is a torsion-free group and \(e\in\mathbb C[G]\) satisfies \(e^2=e\), then \(e=0\) or \(e=1\).Notes
Kaplansky's idempotent conjecture asserts that for a torsion-free group , the complex group algebra has no idempotents besides the trivial ones: if , then or . Like Kaplansky's other group-ring problems it circulated informally, around 1950, before appearing in his 1957 problem list, so the date is conventional [Kaplansky1957Problems].
The conjecture sits below several stronger statements. It follows from the zero-divisor conjecture, since a nontrivial idempotent satisfies , and in appropriate settings it is implied by the Baum-Connes conjecture, which yields the idempotent statement for the many groups for which that conjecture is known [Valette2002BaumConnes]. Analytic and -methods, surveyed by Lück, confirm it for many further geometric classes of groups [Lueck2002L2]. The Kadison-Kaplansky conjecture, asserting the same triviality of idempotents in the reduced group -algebra, is a stronger analytic statement.
For an arbitrary torsion-free group the question remains open; a resolution requires either a torsion-free group whose complex group algebra contains a nontrivial idempotent, or an argument free of geometric and analytic hypotheses.
References (3)
- [Kaplansky1957Problems]
Problems in the theory of rings
Irving Kaplansky · 1957 · misc
- [Lueck2002L2]
-Invariants: Theory and Applications to Geometry and K-Theory
Open ↗Wolfgang Lück · 2002 · misc
- [Valette2002BaumConnes]
Introduction to the Baum–Connes Conjecture
Open ↗Alain Valette · 2002 · misc
The boxed statement is the canonical open formulation — not a stronger variant or a related research program. The status reflects the catalog's last review; do your own literature search before investing serious effort.