Kaplansky Idempotent Conjecture

OPENMajorConjectureProposed c. 1950 · Full conjecture

Canonical statement

If GG is a torsion-free group and eC[G]e\in\mathbb C[G] satisfies e2=ee^2=e, then e=0e=0 or e=1e=1.
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If \(G\) is a torsion-free group and \(e\in\mathbb C[G]\) satisfies \(e^2=e\), then \(e=0\) or \(e=1\).

Kaplansky's idempotent conjecture asserts that for a torsion-free group GG, the complex group algebra C[G]\mathbb C[G] has no idempotents besides the trivial ones: if e2=ee^2=e, then e=0e=0 or e=1e=1. Like Kaplansky's other group-ring problems it circulated informally, around 1950, before appearing in his 1957 problem list, so the date is conventional [Kaplansky1957Problems].

The conjecture sits below several stronger statements. It follows from the zero-divisor conjecture, since a nontrivial idempotent satisfies e(1e)=0e(1-e)=0, and in appropriate settings it is implied by the Baum-Connes conjecture, which yields the idempotent statement for the many groups for which that conjecture is known [Valette2002BaumConnes]. Analytic and L2L^2-methods, surveyed by Lück, confirm it for many further geometric classes of groups [Lueck2002L2]. The Kadison-Kaplansky conjecture, asserting the same triviality of idempotents in the reduced group CC^*-algebra, is a stronger analytic statement.

For an arbitrary torsion-free group the question remains open; a resolution requires either a torsion-free group whose complex group algebra contains a nontrivial idempotent, or an argument free of geometric and analytic hypotheses.

The boxed statement is the canonical open formulation — not a stronger variant or a related research program. The status reflects the catalog's last review; do your own literature search before investing serious effort.