Erdős–Szekeres Convex Polygon Conjecture

OPENLandmarkConjectureProposed 1935 · Standard version

Canonical statement

For k3k\geq3, let f(k)f(k) be the least integer NN such that every NN-point set in the plane with no three collinear contains kk points that are the vertices of their convex hull. Then
f(k)=2k2+1. f(k)=2^{k-2}+1.
View source LaTeX
For \(k\geq3\), let \(f(k)\) be the least integer \(N\)
such that every \(N\)-point set in the plane with no three collinear
contains \(k\) points that are the vertices of their convex hull. Then
\[
  f(k)=2^{k-2}+1.
\]

For k3k\ge3, let f(k)f(k) denote the least NN such that every set of NN points in the plane with no three collinear contains kk points forming a convex polygon. Erdős and Szekeres proved in 1935 that f(k)f(k) is finite, in a paper that helped launch both Ramsey theory and combinatorial geometry, and conjectured the exact value f(k)=2k2+1f(k)=2^{k-2}+1 [ErdosSzekeres1935].

The lower bound is settled: a construction of Erdős and Szekeres exhibits 2k22^{k-2} points in general position with no kk points in convex position, so f(k)2k2+1f(k)\ge2^{k-2}+1, and this is known to be sharp for small values of kk. The upper bound proved much harder. The original argument gave a bound of roughly 4k4^k, and for eighty years improvements affected only lower-order factors. Suk then showed f(k)2k+o(k)f(k)\le2^{k+o(k)}, determining the answer up to sub-exponential factors [Suk2017HappyEnding].

The conjecture thus stands confirmed in the exponent but open in its exact form: a resolution requires eliminating the o(k)o(k) error term and pinning f(k)f(k) down to exactly 2k2+12^{k-2}+1 for every kk.

The boxed statement is the canonical open formulation — not a stronger variant or a related research program. The status reflects the catalog's last review; do your own literature search before investing serious effort.