Odd Perfect Number Conjecture

OPENMajorConjectureProposed Unknown · Full conjecture

Canonical statement

There is no odd positive integer nn satisfying σ(n)=2n\sigma(n)=2n, where σ(n)=dn, d>0d\sigma(n)=\sum_{d\mid n,\ d>0}d.
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There is no odd positive integer \(n\) satisfying \(\sigma(n)=2n\), where \(\sigma(n)=\sum_{d\mid n,\ d>0}d\).

A perfect number equals the sum of its proper divisors, that is, σ(n)=2n\sigma(n)=2n. The even ones are completely understood: by results going back to Euclid and completed by Euler, they are exactly the numbers 2p1(2p1)2^{p-1}(2^p-1) with 2p12^p-1 prime. Whether an odd perfect number exists is a question of genuine antiquity — so old that no first proposer or date can be assigned reliably — and the conjecture is that none does. Euler began its modern study, showing that an odd perfect number would have to take the rigid form pam2p^{a}m^{2} with pp prime and pa1(mod4)p\equiv a\equiv1\pmod 4 [Euler1849Perfect].

Modern work has accumulated severe necessary conditions on a hypothetical example. Nielsen proved that an odd perfect number must have at least nine distinct prime factors [Nielsen2007OddPerfect], and Ochem and Rao showed that it must exceed 10150010^{1500} [OchemRao2012OddPerfect]; a web of congruence restrictions constrains its shape further.

None of these constraints has produced a contradiction, and no example has been found. The problem remains open: a resolution requires either exhibiting an odd nn with σ(n)=2n\sigma(n)=2n or proving that the ever-tightening conditions are jointly unsatisfiable.

The boxed statement is the canonical open formulation — not a stronger variant or a related research program. The status reflects the catalog's last review; do your own literature search before investing serious effort.