Hilbert’s Tenth Problem over
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There is no Turing machine which, on every input polynomial \(f\in\mathbb Z[x_1,\ldots,x_n]\) (where \(n\) is part of the input), halts and correctly decides whether there exists \((q_1,\ldots,q_n)\in\mathbb Q^n\) with \(f(q_1,\ldots,q_n)=0\).Notes
Hilbert's tenth problem asked for an algorithm to decide whether a polynomial equation with integer coefficients has a solution in integers. The present problem is its rational analogue: is there a Turing machine that, given , decides whether vanishes somewhere on ? Equivalently, is the existential first-order theory of decidable? The question took its modern form in 1970, when Matiyasevich, completing work of Davis, Putnam and Robinson, proved that no such algorithm exists over [Matiyasevich1970].
The natural route to a negative answer would be an existential (Diophantine) definition of inside , which would transfer the undecidability over directly. Koenigsmann showed that is definable in by a purely universal formula [Koenigsmann2016ZDefinable], close in logical shape but on the wrong side of the quantifier divide, and Poonen proved undecidability for large subrings of [Poonen2003H10Q]. These definability questions remain the focus of an active program [AIMDefinability2019].
The problem is open in both directions: no decision procedure is known for rational points, and no proof of undecidability either.
References (4)
- [Matiyasevich1970]
Enumerable sets are Diophantine
Yuri Matiyasevich · 1970 · misc
- [Poonen2003H10Q]
Hilbert’s tenth problem and Mazur’s conjecture for large subrings of
Open ↗Bjorn Poonen · 2003 · misc
- [Koenigsmann2016ZDefinable]
Defining in
Open ↗Jochen Koenigsmann · 2016 · misc
- [AIMDefinability2019]
Definability and decidability problems in number theory
Open ↗American Institute of Mathematics · 2019 · misc
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